X^2+9x-3402=0

Solution for X^2+9x-3402=0 equation:

X^2+9X-3402=0

a = 1; b = 9; c = -3402;
Δ = b2-4ac
Δ = 92-4·1·(-3402)
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13689}=117$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-117}{2*1}=\frac{-126}{2}
=-63
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+117}{2*1}=\frac{108}{2}
=54
$